For those of you that want to understand the calculations behind the question here you go. (thanks to PS for supplying the calculation and ?)
Since 65,536 is 2 16, we will need 16 bits for each pixel. We then compute the amount of video memory required:
1. ? bytes = number of pixels * bytes per pixel
2. number of pixels = 800 * 600 = 480,000 pixels
3. bytes per pixel = 16 bits / pixel / ( 8 bits / byte ) = 2 bytes / pixel
4. bytes of video RAM = 480,000 pixels * 2 bytes / pixel = 960,000 bytes
We can again use proportionalities to do additional problems:
• For 1024 by 768 16 bit resolution, we need
960,000 bytes * ( 1024 * 768 pixels / ( 800 * 600 pixels))
= 1,572,864 bytes / ( 2 20 bytes / MB )
= 1.5 MB
• a Truecolor (24 bits per pixel) digital camera image which is 2048 by 1536 pixels requires
960,000 bytes * 24 bits / pixel / ( 16 bits / pixel) * 2048 * 1536 pixels / ( 800 * 600 pixels)
= 9,437,184 bytes / ( 2 20 bytes / MB )
= 9 MB
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